Question

Thực hiện phép tính:

a)(x-2)^3

b)(x+3)^3

c)(2x+3)^2

d)( 1 phần 2 x 3y)^3 +x-1

e)(x-1)^3 - x (x-2)^2 + x-1

f)(x+2)^3 -x^2 (x+6)-8

Answer 1

\(a.\left(x-2\right)^3=x^3-3.x^2.2+3.x.2^2-2^3=x^3-6x^2+12x-8\)

\(b.\left(x+3\right)^3=x^3+3.x^2.2+3.x.2^2+2^3=x^3+6x^2+12x+8\)

\(c.\left(2x+3\right)^2=\left(2x\right)^2+2.2x.3+3^2=4x^2+12x+9\)

\(d.\left(\dfrac{1}{2}.3y\right)^3+x-1=\left(\dfrac{3}{2}y\right)^3+x-1=\dfrac{27}{8}y+x-1\)