\(\dfrac{5}{14}.12\dfrac{1}{2}-\dfrac{5}{14}.5\dfrac{1}{2}\)
\(=\dfrac{5}{14}.\left(12\dfrac{1}{2}-5\dfrac{1}{2}\right)\)
\(=\dfrac{5}{14}.\left(\dfrac{25}{2}-\dfrac{11}{2}\right)\)
\(=\dfrac{5}{14}.\dfrac{14}{2}\)
\(=\dfrac{5}{2}\)
\(\dfrac{5}{14}.12\dfrac{1}{2}-\dfrac{5}{14}.5\dfrac{1}{2}\)
\(=\dfrac{5}{14}.\left(12\dfrac{1}{2}-5\dfrac{1}{2}\right)\)
\(=\dfrac{5}{14}.\left(\dfrac{25}{2}-\dfrac{11}{2}\right)\)
\(=\dfrac{5}{14}.\dfrac{14}{2}\)
\(=\dfrac{5}{2}\)
Bài 1: Thực hiện phép tính sau:
\(a,\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(b,\dfrac{5}{-8}+\dfrac{14}{25}-\dfrac{6}{10}\)
Bài 2 : Thực hiện phép tính
\(a,\dfrac{-7}{2}+\dfrac{3}{4}-\dfrac{17}{12}\)
\(b,-\dfrac{1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
Thực hiện phép tính:
\(d,\dfrac{-5}{12}+0,75\)
\(e,\dfrac{5}{7}.12\dfrac{1}{2}-\dfrac{5}{7}.5\dfrac{1}{2}\)
Bài 1 : Thực hiện phép tính
a/ \(\dfrac{7}{6}\) - \(\dfrac{13}{12}\) + \(\dfrac{3}{4}\)
b/ 1 \(\dfrac{1}{2}\) . \(\dfrac{-4}{5}\) + \(\dfrac{3}{10}\)
c/ \(\dfrac{25}{9}\) . \(\dfrac{3}{10}\) + ( \(\dfrac{-5}{3}\) )\(^2\) . \(\dfrac{7}{10}\) + | \(\dfrac{-25}{3}\) |
Bài 2 : Tìm x , biết
a/ x - \(\dfrac{5}{6}\) = \(\dfrac{1}{4}\)
b/ \(\dfrac{26}{x}\) = \(\dfrac{-13}{-15}\)
( Cần gấp )
Bài 2:Thực hiện phép tính
a)-12:(\(\dfrac{3}{4}\)-\(\dfrac{5}{6}\))\(^2\)
b) (2\(^2\):\(\dfrac{4}{3}\)-\(\dfrac{1}{2}\)).\(\dfrac{6}{5}\)-17
Giúp vs ạ cần gấp
Bài 1: thực hiện phép tính:
\(\dfrac{2}{5}\)-\(\dfrac{1}{7}\).\(\dfrac{1}{2}\)
Bài 1: Thực hiện phép tính sau:
\(c,\dfrac{12}{5}:\dfrac{16}{15}\)
\(d,\dfrac{9}{8}:\dfrac{6}{5}\)
Bài 1 : Thực hiện phép tính
a) \(\dfrac{19}{12}\) + | \(\dfrac{-5}{2}\) | + ( \(\dfrac{3}{2}\) )2
b) \(\dfrac{2}{11}\) . \(\dfrac{16}{9}\) - \(\dfrac{2}{11}\) . \(\dfrac{7}{9}\)
Bài 2 : Tìm x , biết
\(\dfrac{a}{8}\) = \(\dfrac{b}{3}\) và a - b = 55
Thực hiện phép tính:
\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{15}{12}+\dfrac{5}{13}-\dfrac{3}{12}-\dfrac{18}{13}-\dfrac{1}{3}\)
\(14.\dfrac{3}{2}+\dfrac{6}{5}:\left(\dfrac{-2}{5}\right)\)
\(\sqrt{\dfrac{1}{4}+\dfrac{2}{3}-\left(\dfrac{1}{3}\right)^2}\)