a. \(m_{C_2H_5OH}=\dfrac{10.0,8.8}{100}=0,64\left(kg\right)\)
\(n_{C_2H_5OH}=\dfrac{0,64}{46}=\dfrac{8}{575}\left(k-mol\right)\)
\(C_2H_5OH+O_2\rightarrow\left(t^o,men.giấm\right)CH_3COOH+H_2O\)
\(\dfrac{8}{575}\) \(\dfrac{8}{575}\) ( k-mol )
\(m_{CH_3COOH}=\dfrac{8}{575}.60.92\%=0,768\left(kg\right)=768\left(g\right)\)
b.\(m_{dd_{CH_3COOH}}=\dfrac{768.100}{4}=19200\left(g\right)\)