Question

a)(x - 4)^2=4/9

b)(x+1)^2=4/49

Answer 1

`(x-4)^2 = 4/9`

`<=> (x-4)^2 = (2/3)^2`

`<=> x - 4 = -2/3` hoặc `x - 4 = 2/3`

`<=> x = 10/3` hoặc `x = 14/3`

Vậy ....

`(x+1)^2 = 4/49`

`<=> (x+1)^2 = (2/7)^2`

`<=> x + 1= -2/7` hoặc `x + 1 = 2/7`

`<=> x = -9/7` hoặc `x = -5/7`

Vậy ...

Answer 2

\(a,\left(x-4\right)^2=\dfrac{4}{9}\)
\(\left(x-4\right)^2=\dfrac{2^2}{3^2}\)
\(\left(x-4\right)^2=\left(\dfrac{2}{3}\right)^2\)
\(x-4=\dfrac{2}{3}\) hoặc \(x-4=-\dfrac{2}{3}\)
\(x=\dfrac{2}{3}+4\) hoặc \(x=\dfrac{-2}{3}+4\)
\(x=\dfrac{2}{3}+\dfrac{12}{3}\) hoặc \(x=\dfrac{-2}{3}+\dfrac{12}{3}\)
\(x=\dfrac{14}{3}\) hoặc \(x=\dfrac{10}{3}\)
Vậy ......
\(b,\left(x+1\right)^2=\dfrac{4}{49}\)
\(\left(x+1\right)^2=\dfrac{2^2}{7^2}\)
\(\left(x+1\right)^2=\left(\dfrac{2}{7}\right)^2\)
\(x+1=\dfrac{2}{7}\) hoặc \(x+1=-\dfrac{2}{7}\)
\(x=\dfrac{2}{7}-1\) hoặc \(x=\dfrac{-2}{7}-1\)
\(x=\dfrac{2}{7}-\dfrac{7}{7}\) hoặc \(x=\dfrac{-2}{7}-\dfrac{7}{7}\)
\(x=\dfrac{-5}{7}\) hoặc \(x=\dfrac{-9}{7}\)
Vậy ....

Answer 3

Answer 4

`a) (x-4)^2 = 4/9`

`-> (x-4)^2 = (2/3)^2`

`-> x -4 = 2/3` hoặc `x -4 = -2/3`

`-> x = 14/3` hoặc `x = 10/3`

Vậy ..

`b) (x+1)^2 = 4/49` 

`-> (x+1)^2 = (2/7)^2`

`-> x+1 = 2/7` hoặc `x +1 = -2/7` 

`-> x = -5/7` hoặc `x = -9/7`

Vậy..