a) ta có: 34000 = (34)1000 = 811000
92000 = (92)1000 = 811000
=> ....
C2: ta có: 92000 = (32)2000= 34000
b) ta có: 2332 < 2333 = (23)111 = 8111
3223 > 3222 = (32)111 = 9111
=> 8111 < 9111
=> 2332 < 3223
a) cách 1 :34000= 34x1000= (34)1000=811000
92000= 92x1000=(92)1000=811000
ta thấy : 811000=811000 => 34000=92000
Cách 2: 92000= (32)2000= 32x2000=34000
ta thấy ; 34000=34000 => 34000=92000
tk cho mk nha. phần b) để mk nghĩ vì mk mới học lớp 6. mk chắc phần a mk đã làm đúng. kết bạn nha
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2^333=[(2)^3]^111=8^111
3^223 > 3^222
3^222=[(3)^2]^111=9^111
Đáp số:
3^223 > 2^332
a) 34000=(32)2000=92000
92000=(91)2000=92000
Vì 92000=92000
Nên34000=92000
a)34000=32.2000=92000:C1
92000=(32)2000=92000:C2
a) C1: 9^2000=(3^2)^2000=3^4000
=> 9^2000=3^4000
C2 : 3^4000=(3^4)^1000=81^1000
9^2000=(9^2)^1000=81^1000
=>....