Cau a) \(9-64x^2\)=0 => \(64x^2\)=9 => \(x^2\)=\(\frac{9}{64}\)=> x=\(\frac{3}{8}\) hoac x=\(\frac{-3}{8}\). vay nghiem am cua da thuc la -3/8
Cau b) De dang chung minh duoc \(x^2\)+\(y^2\)>= 2xy . <=> 50>= 2xy Suy ra 25>=xy, Suy ra xy<= 25. Vay GTLN cua xy la 25 khi va chi khi \(x^2\)=\(y^2\)=25 => x=y=5 hoac x=y=-5