Question

a.\(\dfrac{4x-5}{x-1}=2+\dfrac{x}{x-1}\)        b.\(\dfrac{7}{x+2}=\dfrac{3}{x-5}\)         c.\(\dfrac{2x+5}{2x}-\dfrac{x}{x+5}=0\)

Answer 1

a: =>4x-5=2x-2+x

=>4x-5=3x-2

=>x=3(nhận)

b: =>7x-35=3x+6

=>4x=41

=>x=41/4

d: =>(2x+5)(x+5)-2x^2=0

=>2x^2+10x+5x+25+2x^2=0

=>15x=-25

=>x=-5/3

Answer 2

a)

\(\dfrac{4x-5}{x-1}=2+\dfrac{x}{x-1}\left(x\ne1\right)\)

suy ra

`4x-5=2(x-1)+x`

`<=>4x-5=2x-2+x`

`<=>4x-2x-x=-2+5`

`<=>x=3(tm)`

b)

\(\dfrac{7}{x+2}=\dfrac{3}{x-5}\left(x\ne-2;x\ne5\right)\)

suy ra

`7(x-5)=3(x+2)`

`<=>7x-35=3x+6`

`<=>7x-3x=6+35`

`<=>4x=41`

`<=>x=41/4(tm)`

c)

\(\dfrac{2x+5}{2x}-\dfrac{x}{x+5}=0\left(x\ne0;x\ne-5\right)\)

suy ra

`(2x+5)(x+5)-2x^2=0`

`<=>2x^2+10x+5x+25-2x^2=0`

`<=>15x=-25`

`<=>x=-5/3(tm)`