`a , x + 1/2 = -6/7`
`=> x = -6/7 - 1/2`
`=> x = -12/14 - 7/14`
`=> x = -19/14`
Vậy: `x = -19/14`
`b, x- 3/4 = 9/8`
`=> x = 9/8 + 3/4`
`=> x = 9/8 + 6/8`
`=> x = 15/8`
Vậy: `x=15/8`
a: \(x+\dfrac{1}{2}=-\dfrac{6}{7}\)
=>\(x=-\dfrac{6}{7}-\dfrac{1}{2}=-\dfrac{12}{14}-\dfrac{7}{14}=-\dfrac{19}{14}\)
b: \(x-\dfrac{3}{4}=\dfrac{9}{8}\)
=>\(x=\dfrac{9}{8}+\dfrac{3}{4}=\dfrac{9}{8}+\dfrac{6}{8}=\dfrac{15}{8}\)
a; \(x+\dfrac{1}{2}\) = - \(\dfrac{6}{7}\)
\(x\) = - \(\dfrac{6}{7}\) - \(\dfrac{1}{2}\)
\(x\) = - \(\dfrac{19}{14}\)
Vậy \(x=-\dfrac{19}{14}\)
b; \(x-\dfrac{3}{4}\) = \(\dfrac{9}{8}\)
\(x\) = \(\dfrac{9}{8}\) + \(\dfrac{3}{4}\)
\(x\) = \(\dfrac{9}{8}\) + \(\dfrac{6}{8}\)
\(x=\dfrac{15}{8}\)
Vậy \(x=\dfrac{15}{8}\)
a: \(x+\dfrac{1}{2}=-\dfrac{6}{7}\)
=>\(x=-\dfrac{6}{7}-\dfrac{1}{2}=-\dfrac{12}{14}-\dfrac{7}{14}=-\dfrac{19}{14}\)
b: \(x-\dfrac{3}{4}=\dfrac{9}{8}\)
=>\(x=\dfrac{9}{8}+\dfrac{3}{4}=\dfrac{9}{8}+\dfrac{6}{8}=\dfrac{15}{8}\)