Question

a) 16. x² =64

b) (5.x-2)-64= -36

c) (2x-10).(5-x)=0

Answer 1

a)16. x² = 64

x² = 64 : 16

x² = 4

x² = 2²

⇒ x = 2

b) (5.x - 2) - 64 = -36

(5.x - 2) = -36 + 64

5.x - 2 = 28

5.x = 28 + 2

5.x = 30

x = 30 : 5

x = 6

c) (2x - 10).(5 - x) = 0

TH1: 2x - 10 = 0

         2x = 0 + 10

         2x = 10

           x = 10 : 2

           x = 5

TH2: 5 - x = 0

              x = 5 - 0

              x = 5

⇒ Vậy x = 5.

 

Answer 2

cứu tui

 

Answer 3

\(16.x^2=64\)

\(=>x^2=64:16\)

\(=>x^2=4\)

\(=>x=2\) hoặc \(x=-2\)

_______

\(\left(5x-2\right)-64=-36\)

\(=>5x-2=\left(-36\right)+64\)

\(=>5x-2=28\)

\(=>5x=28+2\)

\(=>5x=30\)

\(=>x=30:5\)

\(=>x=6\)

_______

\(\left(2x-10\right).\left(5-x\right)=0\)

TH1: \(2x-10=0\)

\(=>2x=0+10\)

\(=>2x=10\)

\(=>x=10:2\)

\(=>x=5\)

TH2: \(5-x=0\)

\(x=5-0\)

\(x=5\)

\(=>x=5\)

Answer 4

a) 16. x² = 64

x² = 64 : 16 

    x^{2 =} 4

     x = 2; -2

b) (5.x - 2) -64 = -36

     (5.x - 2)= -36 + 64 

       5.x - 2 =     28

      5.x = 28-2

      5.x = 26

       x = 26 : 5

       x = 26/5

c) (2x - 10).(5-x) = 0

TH1: 2x - 10 = 0

         2x= 0+10

         2x = 10

         x = 10:2

         x = 5

TH2: 5 -x = 0

        x = 5 - 0

        x = 5