Question

9\(^{x+2}\) + 9\(^x\) = 82

Answer 1

9ˣ⁺² + 9ˣ = 82

9ˣ.(9² + 1) = 82

9ˣ.82 = 82

9ˣ = 82 : 82

9ˣ = 1

9ˣ = 9⁰

x = 0

Answer 2

`9^(x + 2)+ 9^x = 82`

`=> 9^x . 9^2 + 9^x . 1 = 82`

`=> 9^x . 81 + 9^x . 1 = 82`

`=> 9^x . (81+1)=82`

`=> 9^x . 82 = 82`

`=> 9^x=82:82`

`=> 9^x=1`

`=> 9^x=9^0`

`=>x=0`

Vậy: `x=0`

Answer 3

9ˣ⁺² + 9ˣ = 82

9ˣ.(9² + 1) = 82

9ˣ.82 = 82

9ˣ = 82 : 82

9ˣ = 1

9ˣ = 9⁰

\(\Rightarrow\)x = 0