\(\left(\dfrac{9}{5}\right)^7:\left(\dfrac{9}{5}\right)^2=\left(\dfrac{9}{5}\right)^2a-1\)
\(\Leftrightarrow a\cdot\dfrac{81}{25}-1=\left(\dfrac{9}{5}\right)^5\)
\(\Leftrightarrow a\cdot\dfrac{81}{25}=\dfrac{59049}{3125}+1=\dfrac{62174}{3125}\)
\(\Leftrightarrow a=\dfrac{686}{1125}\)
=a⋅8125−1=(95)5⇔a⋅8125−1=(95)5
=a=6861125
\(\left(\dfrac{9}{5}\right)^7:\left(\dfrac{9}{5}\right)^2=\left(\dfrac{9}{5}\right)^{2a-1}\)
⇒\(\left(\dfrac{9}{5}\right)^5=\left(\dfrac{9}{5}\right)^{2a-1}\)
⇒5=2a-1
⇒2a=6
⇒a=3