Question

9² . 2¹¹ phần 16² . 6³ 

Giải thích rõ ràng hơn có được không ạ?

Answer 1

\(\dfrac{9^2.2^{11}}{16^2.6^3}\)

\(=\dfrac{\left(3^2\right)^2.2^{11}}{\left(2^4\right)^2.2^3.3^3}\)

\(=\dfrac{3^4.2^{11}}{2^8.2^3.3^3}\)

\(=\dfrac{3^4.2^{11}}{2^{11}.3^3}\)

\(=3\)

Answer 2

`(9^2 . 2^11)/(16^2  . 6^3)`

`=((3^2)^2 . 2^11)/((2^4)^2. 2^3 . 3^3)`

`= (3^4 . 2^11)/(2^8 . 2^3 . 3^3)`

`= (3^4 . 2^11)/(2^11 . 3^3)`

`= 3`