Question

7x^2(5x-10)+x(10-5x)=0

Answer 1

=>x(5x-10)(7x-1)=0

=>x=0; x=2;x=1/7

Answer 2

`7x^2(5x-10)+x(10-5x)=0`

`<=>7x^2(5x-10)-x(5x-10)=0`

`<=>5x(x-2)(7x-1)=0`

\(\Leftrightarrow\left[{}\begin{matrix}5x=0\\x-2=0\\7x-1=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=\dfrac{1}{7}\end{matrix}\right.\)