\(=\dfrac{13}{2}-\dfrac{7}{3}:\dfrac{7}{15}=\dfrac{13}{2}-5=\dfrac{13}{2}-\dfrac{10}{2}=\dfrac{3}{2}\)
\(\dfrac{13}{2}-\dfrac{7}{3}:\dfrac{7}{15}\)
\(=\dfrac{13}{2}-5\)
\(=\dfrac{3}{2}\)
\(=\dfrac{13}{3}-\dfrac{7}{3}:\dfrac{7}{15}=\dfrac{3}{2}\)
\(=\dfrac{13}{2}-\dfrac{7}{3}:\dfrac{7}{15}=\dfrac{13}{2}-5=\dfrac{13}{2}-\dfrac{10}{2}=\dfrac{3}{2}\)
\(\dfrac{13}{2}-\dfrac{7}{3}:\dfrac{7}{15}\)
\(=\dfrac{13}{2}-5\)
\(=\dfrac{3}{2}\)
\(=\dfrac{13}{3}-\dfrac{7}{3}:\dfrac{7}{15}=\dfrac{3}{2}\)
VÒNG 2
Bài 1: Mèo con nhanh nhẹn
\(\dfrac{1}{2}\) + \(\dfrac{1}{12}\) | 2 + \(\dfrac{1}{6}\) | \(\dfrac{1}{20}\) | 1 - \(\dfrac{1}{9}\) | |
\(\dfrac{1}{15}\) + \(\dfrac{2}{15}\) | \(\dfrac{1}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{7}{12}\) | \(\dfrac{4}{12}\) | |
\(\dfrac{9}{14}\)+ \(\dfrac{1}{14}\) | 1 + \(\dfrac{1}{6}\) | \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) | \(\dfrac{1}{3}\) - \(\dfrac{2}{9}\) | |
\(\dfrac{3}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{1}{5}\) | 1 - \(\dfrac{8}{9}\) | ||
\(\dfrac{5}{7}\) | 1 - \(\dfrac{2}{3}\) | \(\dfrac{1}{3}\) + \(\dfrac{5}{9}\) |
Bài 7: Tính
a) \(4\dfrac{2}{5}x8\dfrac{3}{4}-2\dfrac{3}{4}=...............................\)
b) \(2\dfrac{2}{3}+1\dfrac{2}{5}-\dfrac{2}{15}\)=..............................................
c) \(3\dfrac{1}{3}-2\dfrac{2}{3}+1\dfrac{5}{6}=...............................\)
Tính hợp lí :
A = \(\dfrac{-2}{9}\) + \(\dfrac{-3}{4}\) + \(\dfrac{3}{5}\) + \(\dfrac{1}{15}\) + \(\dfrac{1}{57}\) + \(\dfrac{1}{3}\) + \(\dfrac{-1}{36}\)
B = \(\dfrac{1}{2}\) + \(\dfrac{-1}{5}\) + \(\dfrac{-5}{7}\) + \(\dfrac{1}{6}\) + \(\dfrac{-3}{35}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{41}\)
C = \(\dfrac{-1}{2}\) + \(\dfrac{3}{5}\) + \(\dfrac{-1}{9}\) + \(\dfrac{1}{127}\) + \(\dfrac{-7}{18}\) + \(\dfrac{4}{35}\) + \(\dfrac{2}{7}\)
a. Tìm a, biết: 1 - ( 5\(\dfrac{4}{9}\) + a - 7\(\dfrac{7}{18}\) ) : 15\(\dfrac{3}{4}\) = 0
b. Tính b = ( \(\dfrac{2}{15}\) + \(\dfrac{5}{3}\) - \(\dfrac{3}{5}\) ) : ( \(4\dfrac{2}{3}\) - \(2\dfrac{1}{2}\) )
\(\dfrac{15}{14}\) : \(\dfrac{10}{21}\) x \(\dfrac{1}{5}\)
\(5\) x \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\)
\(7\) : \(\dfrac{1}{5}\) - \(\dfrac{1}{5}\)
\(6\) + \(\dfrac{1}{5}\) : \(2\)
\(8\) - \(\dfrac{1}{5}\) x \(7\)
\(\dfrac{\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}\right):\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{1}{15}\right)}{\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}\right):\left(\dfrac{1}{4}-\dfrac{1}{6}\right)}=\)
Bài 2: (Đề1) Tính
\(4\dfrac{2}{3}+3\dfrac{2}{7}\)=..........................
\(8\dfrac{5}{9}:5\dfrac{1}{2}\) =..........................
\(6\dfrac{5}{7}:2\dfrac{1}{6}\) =..........................
\(1\dfrac{3}{4}x2\dfrac{5}{6}\) =..........................
\(5\dfrac{3}{4}-2\) =..........................
Tính A= \(\dfrac{1}{2}\)- \(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)-\(\dfrac{4}{5}\)+\(\dfrac{5}{6}\)-\(\dfrac{6}{7}\)-\(\dfrac{6}{5}\)+\(\dfrac{4}{5}\)-\(\dfrac{3}{4}\)+\(\dfrac{2}{3}\)-\(\dfrac{1}{2}\)
Tìm a
a) \(2\dfrac{3}{4}-a+\dfrac{1}{4}=1\dfrac{1}{2}\)
b)3\(\dfrac{1}{4}-a-1\dfrac{3}{4}=\dfrac{7}{8}\)
c) 2\(\dfrac{5}{6}-1\dfrac{1}{2}-a=\dfrac{1}{6}\)