\(ĐK:x\in Z;x\ne1\\ 5⋮\left(x-1\right)=>x-1\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\\ =>x\in\left\{0;2;-4;6\right\}\left(TMDK\right)\)
`5 \vdots (x-1)`
=>x-1 in Ư_5`
Mà `Ư_5={+-1;+-5}`
`@x-1=1=>x=2`
`@x-1=-1=>x=0`
`@x-1=5=>x=6`
`@x-1=-5=>x=-4`
Vậy `x={-4;-;2;6}`
\(x-1\inƯ\left(5\right)\)
\(Ư\left(5\right)=\left\{1;-1;5;-5\right\}\)
\(Với \) x -1 =1
=> x=2
\(Với\) x - 1 = -1
=> x=0
\(Với\) x -1 =5
=> x=6
\(Vớix-1=-5\\ =>x=-4\)
Vậy...
\(5⋮\left(x-1\right)\\ \rightarrow x-1\in U\left(5\right)\\ \rightarrow x-1\in\left\{\pm1;\pm5\right\}\\ \rightarrow\left[{}\begin{matrix}x-1=1\\x-1=5\\x-1=-1\\x-1=-5\end{matrix}\right.\\ \rightarrow\left[{}\begin{matrix}x=2\\x=6\\x=0\\x=-4\end{matrix}\right.\)
