Question

\(5\) x \(\left(-\dfrac{2}{5}\right)^2\) + 2 x \(\left(-\dfrac{2}{5}\right)\) + 4 x \(\left(-\dfrac{2}{5}\right)^0\)

 

Answer 1

`5 xx (-2/5)^2 + 2 xx (-2/5) + 4 xx (-2/5)^0`

`= 5 xx 4/25 + 2 xx (-2/5) + 4 xx 1`

`= 1 xx 4/5 + 2 xx (-2/5) + 4 xx 1`

`= 4/5 + -4/5 + 4`

`= 0 + 4`

`= 4 `

Answer 2

\(5.\left(-\dfrac{2}{5}\right)^2+2.\left(-\dfrac{2}{5}\right)+4.\left(-\dfrac{2}{5}\right)^0\)
\(=5.\dfrac{4}{25}+\dfrac{-4}{5}+4.1\)
\(=\dfrac{4}{5}-\dfrac{4}{5}+4\)
\(=\dfrac{4}{5}-\dfrac{4}{5}+\dfrac{20}{5}\)
\(=\dfrac{4-4+20}{5}\)
\(=\dfrac{20}{5}\)

\(=4\)

Answer 3

\(=5\times\dfrac{2}{25}+\left(-\dfrac{4}{5}\right)+4\times1\)

\(=\dfrac{2}{5}-\dfrac{4}{5}+4\)

\(=\dfrac{2}{5}-\dfrac{4}{5}+\dfrac{20}{5}\)

\(=\dfrac{2-4+20}{5}=\dfrac{18}{5}\)