\(\Rightarrow4x^2-4x-3x^2+15-x^2=x-3-x+4\)
\(\Rightarrow4x=14\Rightarrow x=\dfrac{7}{2}\)
\(4x\left(x-1\right)-3\left(x^2-5\right)-x^2=\left(x-3\right)-\left(x-4\right)\\ \Leftrightarrow4x^2-4x-3x^2+15-x^2=x-3-x+4\\ \Leftrightarrow-4x=-14\\ \Leftrightarrow x=\dfrac{7}{2}\)