Question

4x(5-x)-8x(5-x)=0

Answer 1

\(4x\left(5-x\right)-8x\left(5-x\right)=0\)

\(\Rightarrow x\left(5-x\right).\left(4-8\right)=0\)

\(\Rightarrow x\left(5-x\right)=0\)

\(\Rightarrow\left\{{}\begin{matrix}x=0\\5-x=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

Vậy \(x\in\left\{0;5\right\}\)

Chúc bạn học tốt!!!

Answer 2

Ta có:4x(5-x)-8x(5-x)=0<=>4x(5-x)-2.4x(5-x)<=>4x(5-x)(1-2)=0

<=>-4x(5-x)=0

=>4x=0 hoặc 5-x=0=>x=0 hoặc x=5

Vậy S={0;5}

Answer 3

<=> 20x-4x²-40x+8x²=0
<=> 4x²-20x=0
<=> x(4x-20)=0
<=> \(\left\{{}\begin{matrix}x=0\\4x-20=0< =>4x=20< =>x=5\end{matrix}\right.\)

Answer 4

\(4x\left(5-x\right)-8x\left(5-x\right)=0\\ \Leftrightarrow20x-4x^2-40x+8x^2=0\\ \Leftrightarrow4x^2-20x=0\\ \Leftrightarrow4x\left(x-5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}4x=0\\x-5=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

vậy phương trình có tập nghiệm là S={0;5}

Answer 5

\(4x\left(5-x\right)-8x\left(5-x\right)=0\Leftrightarrow\left(4x-8x\right)\left(5-x\right)=0\Leftrightarrow-4x\left(5-x\right)=0\Leftrightarrow\left[{}\begin{matrix}-4x=0\\5-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)