\(\Leftrightarrow\dfrac{4}{x-1}-\dfrac{5}{x-2}=-3\)
\(\Leftrightarrow4x-8-5x+5+3\left(x-1\right)\left(x-2\right)=0\)
\(\Leftrightarrow3\left(x^2-3x+2\right)-x-3=0\)
\(\Leftrightarrow3x^2-9x+6-x-3=0\)
\(\Leftrightarrow3x^2-10x+3=0\)
=>(3x-1)(x-3)=0
=>x=1/3 hoặc x=3