\(45\left(x+2\right)=-3\\ \Rightarrow x+2=\dfrac{-1}{15}\\ \Rightarrow x=-\dfrac{1}{15}-2\\ \Rightarrow x=-\dfrac{31}{15}\)
45x+90=-3
45x=-3-90
45x=-93
x=-\(\dfrac{-93}{45}\)
x=\(\dfrac{-31}{15}\)
45.(x+2)=-3
=>45x+90=-3
=>45x=-3-90
=>45x=-93
=>x\(\left\{{}\begin{matrix}x=\dfrac{-93}{45}\\x=\dfrac{-31}{15}\end{matrix}\right.\)