Question

3^x + x^2 = 1

Giúp mình nha

Answer 1

o0o I am a studious person o0o:làm vừa ngu xi vừa vớ vẩn còn đổi li-ke y hêt Viêt Hoàng

=0 =>3^x+x²=3⁰+0²=1+0=1 (TM)

Answer 2

\(3x+x^2=1\)

\(=>x^2+3x-1=0\)

\(=>x^2+2.x.\frac{3}{2}+\frac{9}{4}-\frac{5}{4}=0\)

\(=>\left(x+\frac{3}{2}\right)^2-\frac{5}{4}=0\)

\(=>\left(x+\frac{3}{2}\right)^2=\frac{5}{4}\)

\(=>\orbr{\begin{cases}x+\frac{3}{2}=-\sqrt{\frac{5}{4}}\\x+\frac{3}{2}=\sqrt{\frac{5}{4}}\end{cases}}\)

\(=>\orbr{\begin{cases}x=-2,61.....\\x=2,61......\end{cases}}\)