3x - |2x + 1| = 2
=> |2x + 1| = 3x - 2
+TH1: 2x + 1 = 3x - 2
=> 3x - 2x = 1 + 2
=> x = 3
+TH2: 2x + 1 = -(3x - 2)
=> 2x + 1 = -3x + 2
=> 2x + 1 = 2 - 3x
=> 2x + 3x = 2 - 1
=> 5x = 1
=> x = 1/5 ( ko thỏa mãn )
Đúng 2
Bình luận (3)
\(\Leftrightarrow\left|2x+1\right|=3x-2\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+1=3x-2\\2x+1=2-3x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\5x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{5}\end{matrix}\right.\)
Đúng 4
Bình luận (0)
