\(\left(3x-16\right)\cdot49=2\cdot343\)
=>\(3x-16=2\cdot343:49\)
=>\(3x-16=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\dfrac{30}{3}=10\)
\(\left(3\cdot x-16\right)\cdot49=2\cdot343\\ \Rightarrow\left(3\cdot x-16\right)\cdot49=686\\ \Rightarrow3\cdot x-16=686:49\\ \Rightarrow3\cdot x-16=14\\ \Rightarrow3\cdot x=14+16\\ \Rightarrow3\cdot x=20\\ \Rightarrow x=\dfrac{20}{3}\)
Vậy \(x=\dfrac{20}{3}\)
\(\left(3x-16\right).49=2.343\)
\(=>\left(3x-16\right).49=686\)
\(=>3x-16=686:49\)
\(=>3x=14+16\)
\(=>3x=30\)
\(=>x=30:3\)
\(=>x=10\)
Vậy x = 10.
\(#NqHahh\)
(3.x-16).49=2.343
(3.x-16).49=686
(3.x-16) =686:49
3.x-16 =14
3.x =14+16
3.x =30
x =30:3
x =10
Vậy x=10
