\(3\sqrt{x-3}=6\) (ĐK: \(x\ge3\))
\(\Leftrightarrow\sqrt{x-3}=\dfrac{6}{3}\)
\(\Leftrightarrow\sqrt{x-3}=2\)
\(\Leftrightarrow x-3=2^2\)
\(\Leftrightarrow x-3=4\)
\(\Leftrightarrow x=4+3\)
\(\Leftrightarrow x=7\left(tm\right)\)
Vậy: ...
\(3\sqrt{x-3}=6\\ \Leftrightarrow\sqrt{x-3}=6:3\\ \Leftrightarrow\sqrt{x-3}=2\\ \Leftrightarrow\left(\sqrt{x-3}\right)^2=2^2\\ \Leftrightarrow x-3=4\\ \Leftrightarrow x=4+3\\ \Leftrightarrow x=7.\)