35:(2x+3)=2
=>\(2x+3=\dfrac{35}{2}\)
=>\(2x=\dfrac{35}{2}-3=\dfrac{35}{2}-\dfrac{6}{2}=\dfrac{29}{2}\)
=>\(x=\dfrac{29}{2}:2=\dfrac{29}{4}\)
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+211\right)=23632\)
=>\(211x+\left(1+2+...+211\right)=23632\)
=>\(211x+211\times\dfrac{212}{2}=23632\)
=>211x+22366=23632
=>211x=23632-22366=1266
=>x=6
`35 : (2x + 3) = 2`
`=> 2x + 3 = 35/2`
`=> 2x = 29/2`
`=> x = 29/4`
Vậy `x = 29/4`
`(x + 1) + (x + 2) + ... + (x + 211) = 23632`
`=> x + 1 + x + 2 + ... + x + 211 = 23632`
`=> (x + x + .. + x) + ( 1 + 2 + ... + 211) = 23632`
số số hạng là : `( 211 - 1) : 1 + 1 = 211`(số số hạng)
tổng là : `(211 + 1) xx 211 : 2 = 22366`
`=> 211x + 22366 = 23632`
`=> 211x = 1266`
`=> x =6`
Vậy `x = 6`