\(-\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)=-\dfrac{3}{17}+\dfrac{3}{17}+\dfrac{2}{3}=\dfrac{2}{3}\)
-3/17+(2/3+3/17)
=-3/17+2/3+3/17
=(-3/17+3/17)+2/3
=0+2/3
=2/3
=\(\dfrac{-3}{17}=\dfrac{2}{3}+\dfrac{3}{17}\)
=(\(\dfrac{-3}{17}+\dfrac{3}{17}\))+\(\dfrac{2}{3}\)
=\(0+\dfrac{2}{3}\)
=\(\dfrac{2}{3}\)