A = \(\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)\)
= \(\dfrac{3}{17}+\dfrac{43}{51}\)
= \(\dfrac{52}{51}\)
Vậy A = \(\dfrac{52}{51}\)
`3/17 + (2/3 + 3/17)`
`= 3/17 + 2/3 + 3/17`
`= 3/17 + 3/17 + 2/3`
`= 6/17 + 2/3`
`= 18/51 + 34/51`
`= (18 + 34)/51 `
`= 52/51`