\(3x+3x+1+3x+2+3x+3=29160\Rightarrow3x+3x+3x+3x=29160-1-2-3\)
\(\Rightarrow12x=29154\Rightarrow x=\dfrac{4859}{2}=2429,5\)
3x+3x+1+3x+2+3x+3=29160
➩3x.4=29160-1-2-3
⇔12x=29154
⇔x=2429.5
3x+3x+1+3x+2+3x+3=29160
➩3x.4=29160-1-2-3
➩12x=29154
➩x=2429.5
Ta có: \(3x+3x+1+3x+2+3x+3=29160\)
\(\Leftrightarrow12x=29154\)
hay x=2429,5