\(\left|3-2x\right|=5\)
\(\Rightarrow\left[{}\begin{matrix}3-2x=5\\3-2x=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=1\end{matrix}\right.\)
Vậy...
\(\left|3-2x\right|=5\)
\(\Rightarrow\left[{}\begin{matrix}3-2x=5\\3-2x=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=3-5=-2\\2x=3-\left(-5\right)=8\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)
Vậy \(x\in\left\{-1;4\right\}\)
2x = 5 + 3
2x = 8
x =8 : 2
x=4 quá easy
\(\left|3-2x\right|=5\)
\(\Leftrightarrow\left[{}\begin{matrix}-2x+3=5\\-2x+3=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-2x=2\\-2x=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)