Question

2x/x+1 + 3-2x/x =0

Answer 1

`[2x]/[x+1]+[3-2x]/x=0`         `ĐK: x \ne -1,x \ne 0`

`<=>[2x^2+(3-2x)(x+1)]/[x(x+1)]=0`

  `=>2x^2+3x+3-2x^2-2x=0`

`<=>x=-3` (t/m)

Vậy `S={-3}`

Answer 2

 (2x-1)(x+3)(2-x)=0

=>2x-1 =0 hoặc x+3=0 hoặc 2-x=0

=>x=1/2 hoặc x=-3 hoặc x=2

Answer 3

\(\dfrac{2x}{x+1}-\dfrac{2x-3}{x}=0\)

\(\Leftrightarrow2x^2-\left(2x-3\right)\left(x+1\right)=0\)

\(\Leftrightarrow2x^2-\left(2x^2+2x-3x-3\right)=0\)

\(\Leftrightarrow2x^2-2x^2+x+3=0\)

=>x+3=0

hay x=-3