\(2x^2-10x-3x-2x^2-26=0\)
\(-13x-26=0\)
\(x=-2\)
2x2−10x−3x−2x2−26=02x2−10x−3x−2x2−26=0
13x−26=0−13x−26=0
x=−2
\(\Leftrightarrow2x^2-10x-3x-2x^2=26\)
hay x=-2
\(2x\left(x-5\right)-x\left(3+2x\right)=26\)
⇔\(2x^2-10x-\left(3x+2x^2\right)=26\)
⇔\(2x^2-10x-3x-2x^2=26\)
⇔\(\left(2x^2-2x^2\right)-\left(10x+3x\right)=26\)
⇔\(-13x=26\)
⇔\(x=\dfrac{26}{-13}\)
⇔\(x=-2\)