\(2x\left(x+2\right)\)
\(=>\left[{}\begin{matrix}2x=0\\x+2=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
\(=>x\in\left\{0;-2\right\}\)
`2x^2+4x =0`
`2x(x+2)= 0`
`<=>x = 0` hoặc `x = -2`
\(2x^2+4x=0\\ \Leftrightarrow2x\left(x+2\right)=0\\\Leftrightarrow\left\{{}\begin{matrix}2x=0\\x+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
Vậy x=0 ;x=-2