\(2x-\sqrt{2x-1}=3\left(ĐK:x\ge\frac{1}{2}\right)\)
\(\Leftrightarrow2x-3=\sqrt{2x-1}\)
\(\Leftrightarrow4x^2-12x+9=2x-1\)
\(\Leftrightarrow4x^2-14x+10=0\)
\(\Leftrightarrow\left(4x^2-4x\right)-\left(10x-10\right)=0\)
\(\Leftrightarrow4x\left(x-1\right)-10\left(x-1\right)=0\)
\(\Leftrightarrow2\left(x-1\right)\left(2x-5\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\2x-5=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=\frac{5}{2}\end{array}\right.\)
Đúng 0
Bình luận (1)
