\(\left(2x-3\right)^{2022}=\left(2x-3\right)^{2021}\)
\(\left(2x-3\right)^{2021}\left(2x-3-1\right)=0\)
\(\left(2x-3\right)^{2021}\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=2\end{matrix}\right.\)
Ta có:
\(\left(2x-3\right)^{2022}=\left(2x-3\right)^{2021}\)
\(\Rightarrow\left(2x-3\right)^{2022}-\left(2x-3\right)^{2021}=0\)
\(\Rightarrow\left(2x-3\right)^{2021}\left[\left(2x-3\right)-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-3=0\\2x-3-1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=3\\2x=4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{3}{2};2\right\}\).
\(Toru\)
^ cái dấu này có phải là mũ ko bạn
(2x - 3)²⁰²² = (2x - 3)²⁰²¹
(2x - 3)²⁰²² - (2x - 3)²⁰²¹ = 0
(2x - 3)²⁰²¹.(2x - 3 - 1) = 0
(2x - 3).(2x - 4) = 0
2x - 3 = 0 hoặc 2x - 4 = 0
*) 2x - 3 = 0
2x = 3
x = 3/2
*) 2x - 4 = 0
2x = 4
x = 2
Vậy x = 3/2; x = 2
