`2x-1/5=5`
`2x=5+1/5`
`2x=26/5`
`x=26/5 :2`
`x=13/5`
\(2x-\dfrac{1}{5}=5\)
\(2x=5+\dfrac{1}{5}\)
\(2x=\dfrac{26}{5}\)
\(x=\dfrac{13}{5}\)
\(2x-\dfrac{1}{5}=5\)
\(\Leftrightarrow2x=\dfrac{26}{5}\)
\(\Rightarrow x=\dfrac{13}{5}\)
Ta có: \(\dfrac{2x-1}{5}=5\)
\(\Leftrightarrow2x-1=25\)
\(\Leftrightarrow2x=26\)
hay x=13
\(2x-\dfrac{1}{5}=5\)
\(2x=5+\dfrac{1}{5}\)
\(2x=\dfrac{26}{5}\)
\(x=\dfrac{26}{5}:2\)
\(x=\dfrac{13}{5}\)
2x −\(\dfrac{1}{5}\) = 5
2x = 5 + \(\dfrac{1}{5}\)
2x = \(\dfrac{26}{5}\)
x= \(\dfrac{26}{5}\) : 2
x = \(\dfrac{13}{5}\)
Vậy x = \(\dfrac{13}{5}\)