`2 |x-1|=4`
`|x-1|=4:2`
`|x-1|=2`
`@TH1:`
`x-1=2`
`x=2+1`
`x=3`
`@TH2:`
`x-1=-2`
`x=-2+1`
`x=-1`
Vậy `x = {3;-1}`
=>|x-1|=2
=>x-1=2 hoặc x-1=-2
=>x=3 hoặc x=-1
\(2\left|x-1\right|=4\)
\(\left|x-1\right|=4:2\)
\(\left|x-1\right|=2\)
\(x-1=\pm2\)
\(\Rightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2+1\\x=-2+1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
Vậy ..
2|x−1|=42|x-1|=4
|x−1|=4:2|x-1|=4:2
|x−1|=2|x-1|=2
∘TH1:∘TH1:
x−1=2x-1=2
x=2+1x=2+1
x=3x=3
∘TH2:∘TH2:
x−1=−2x-1=-2
x=−2+1x=-2+1
x=−1x=-1
Vậy x={3;−1}
