\(\left(2x-1\right)^3=125\)
\(\Rightarrow2x-1=5\Rightarrow2x=6\Rightarrow x=3\)
(2x - 1)3 = 125
<=> (2x - 1)3 = 53
<=> 2x - 1 = 5
<=> 2x = 6
<=> x = 3
\(\Rightarrow2x-1=5\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
(2x-1)^3 = 5^3
(2x-1) = 5
2x = 5 + 1
2x = 6
x = 6 :2
x= 3
\(( 2x - 1 ) ^3 = 125 \)
\(( 2x - 1 ) ^3 = 5^3 \)
➝ \(2x - 1 = 5 \)
➝ \(2x = 6 \)
➝ \(x = 3 \)
Vậy \(x = 3 \)