\(\dfrac{11}{4}+\dfrac{12}{4}-0=\dfrac{23}{4}-0=\dfrac{23}{4}\)
`2 3/4 + 2 4/4 - 0`
`= 11/4 + 3 - 0`
`= 23/4 - 0`
`= 23/4`
Sắp xếp các số sau theo thứ tự từ bé đến lớn: \(0;\dfrac{1}{3};\dfrac{1}{5};1;\dfrac{3}{4};2;\dfrac{4}{3};\dfrac{5}{2};\dfrac{6}{2}\)
Tính A= \(\dfrac{1}{2}\)- \(\dfrac{2}{3}\)+\(\dfrac{3}{4}\)-\(\dfrac{4}{5}\)+\(\dfrac{5}{6}\)-\(\dfrac{6}{7}\)-\(\dfrac{6}{5}\)+\(\dfrac{4}{5}\)-\(\dfrac{3}{4}\)+\(\dfrac{2}{3}\)-\(\dfrac{1}{2}\)
Bài 2: (đề 2) Tìm y
a) \(2\dfrac{2}{5}-y:2\dfrac{3}{4}=1\dfrac{1}{2}\) b) \(1\dfrac{1}{4}+2\dfrac{1}{5}\) x \(y=2\dfrac{3}{5}\)
c) \(2\dfrac{4}{5}-2\dfrac{1}{4}:y=\dfrac{3}{4}\) c) \(x:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\)
a,(\(\dfrac{4}{5}+\dfrac{2}{3}\)) x 2 x \(\dfrac{3}{4}\)
b,\(\dfrac{4}{5}\) x \(\dfrac{2}{3}\) x \(\dfrac{3}{4}\)
tính
\(4\dfrac{1}{5}\times2\dfrac{1}{4}=\) \(3\dfrac{3}{5}\times1\dfrac{2}{3}=\)
\(4\dfrac{1}{5}:2\dfrac{1}{4}=\) \(3\dfrac{3}{5}:1\dfrac{2}{3}=\)
bài 4: (đề 2) Tìm a
a) \(2\dfrac{3}{4}-a+\dfrac{1}{4}=1\dfrac{1}{2}\) b) \(3\dfrac{1}{4}-a-1\dfrac{3}{4}=\dfrac{7}{9}\) c) \(2\dfrac{5}{6}-1\dfrac{1}{2}-a=\dfrac{1}{6}\)
Bài 7: Tính
a) \(4\dfrac{2}{5}x8\dfrac{3}{4}-2\dfrac{3}{4}=...............................\)
b) \(2\dfrac{2}{3}+1\dfrac{2}{5}-\dfrac{2}{15}\)=..............................................
c) \(3\dfrac{1}{3}-2\dfrac{2}{3}+1\dfrac{5}{6}=...............................\)
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
Bài 1: (đề 2) Tính
a) \(2\dfrac{3}{8}:3\dfrac{3}{4}x2\dfrac{2}{3}\)=............
b) \(1\dfrac{1}{2}:\dfrac{7}{3}:2\dfrac{5}{6}\)=............
c) \(4\dfrac{2}{3}-1\dfrac{3}{4}:2\dfrac{2}{5}\)=............
Bài 3 Tìm x
\(\dfrac{1}{2}:3+x=1\dfrac{2}{3}\)
\(2\dfrac{3}{4}-x=\dfrac{5}{6}+\dfrac{2}{3}\)
\(5\dfrac{4}{10}-x\) X\(\dfrac{3}{4}=\dfrac{2}{3}\)
