\(27-x^3=3^3-x^3=\left(3-x\right)\left(9+3x+x^2\right)\)
\(=\left(3-x\right)\left(3^2+3x+x^2\right)\\ =\left(3-x\right)\left(9+3x+x^2\right)\)
\(27-x^3=3^3-x^3=\left(3-x\right)\left(3^2+3x+x^2\right)=\left(3-x\right)\left(9+3x+x^2\right)\)
27 − x^3 = 3^3 − x^3 = ( 3 − x ) ( 9 + 3x + x^2 )