\(=\dfrac{25}{100}-\dfrac{3}{2}+\dfrac{1}{2}.\dfrac{12}{5}=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{6}{5}=\dfrac{5}{20}-\dfrac{30}{20}+\dfrac{24}{20}=\dfrac{-1}{20}\)
\(\dfrac{25}{100}-\dfrac{3}{2}+\dfrac{5}{10}.\dfrac{12}{5}\)
= \(\dfrac{25}{100}-\dfrac{3}{2}+\dfrac{1}{10}.\dfrac{12}{1}\)
= \(\dfrac{25}{100}-\dfrac{3}{2}+\dfrac{12}{10}=\dfrac{6}{5}\)
= \(\dfrac{25}{100}-\dfrac{150}{100}+\dfrac{120}{100}\)
= \(\dfrac{-125}{100}+\dfrac{120}{100}\)
= \(\dfrac{-5}{100}\)= \(\dfrac{-1}{20}\)