=>-1/3(2x-5)=3/2+2/3=13/6
=>2x-5=-13/6:1/3=-13/2
=>2x=-3/2
hay x=-3/4
\(\dfrac{-2}{3}-\dfrac{1}{3}\left(2x-5\right)=\dfrac{3}{2}\)
\(\dfrac{1}{3}\left(2x-5\right)=\dfrac{-2}{3}-\dfrac{3}{2}\)
\(\dfrac{1}{3}\left(2x-5\right)=-\dfrac{13}{6}\)
\(2x-5=\dfrac{-13}{6}:\dfrac{1}{3}\)
\(2x-5=\dfrac{-13}{2}\)
\(2x=\dfrac{-13}{2}+5\)
\(2x=\dfrac{-3}{2}\)
\(x=\dfrac{-3}{2}:2\)
\(x=\dfrac{-3}{4}\)
Vậy \(x=\dfrac{-3}{4}\)
\(-\dfrac{2}{3}-\dfrac{1}{3}\left(2x-5\right)=\dfrac{3}{2}\)
\(-\dfrac{1}{3}\left(2x-5\right)=\dfrac{3}{2}+\dfrac{2}{3}\)
\(-\dfrac{1}{3}\left(2x-5\right)=\dfrac{13}{6}\)
\(2x-5=-\dfrac{13}{2}\)
\(2x=-\dfrac{13}{2}+5\)
\(2x=-\dfrac{3}{2}\)
\(x=-\dfrac{3}{2}:2\)
\(x=-\dfrac{3}{4}.\)
\(Vậy.....\)
\(-\dfrac{2}{3}-\dfrac{1}{3}\left(2x-5\right)=\dfrac{3}{2}\)
\(\dfrac{1}{3}\left(2x-5\right)=-\dfrac{2}{3}-\dfrac{3}{2}\)
\(\dfrac{1}{3}\left(2x-5\right)=\dfrac{-13}{6}\)
\(2x-5=-\dfrac{13}{6}:\dfrac{1}{3}\)
\(2x-5=-\dfrac{13}{2}\)
\(2x=-\dfrac{13}{2}+5\)
\(2x=-\dfrac{3}{2}\)
\(x=-\dfrac{3}{2}:2\)
\(x=-\dfrac{3}{4}\)
