Question

1)X²+√x 2)(√2 + 1)²-4√2

Answer 1

1: \(x^2+\sqrt{x}=\sqrt{x}\left(x\sqrt{x}+1\right)\)

\(=\sqrt{x}\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+!\right)\)

2: \(\left(\sqrt{2}+1\right)^2-4\sqrt{2}\)

\(=3+2\sqrt{2}-4\sqrt{2}\)

=3-2*căn 2

=(căn 2-1)^2