\(1500:\left(30x+40\right):2=30\)
⇔ \(750:\left(30x+40\right)=30\)
⇒ \(30x+40=750:30=25\)
⇔ \(30x=-15\)
⇔ \(x=-\dfrac{1}{2}\)
Sửa đề: \(1500:\left[\left(30x+40\right):2\right]=30\)
\(\Rightarrow\left(30x+40\right):2=50\)
\(\Rightarrow30x+40=100\)
\(\Rightarrow30x=60\Rightarrow x=2\)
1500 : [(30 . x + 40)] : 2 = 30
(30 . x + 40) : 2 = 1500 : 30
(30 . x + 40) : 2 = 50
30 . x + 40 = 50 . 2
30 . x + 40 = 100
30 . x = 100 - 40
30 . x = 60
x = 60 : 30
x = 2
Trả lời:
1500:[(30.x+40)]:2=30
(30 . x + 40) : 2 = 1500 : 30
(30 . x + 40) : 2 = 50
30 . x + 40 = 50 . 2
30 . x + 40 = 100
30 . x = 100 - 40
30 . x = 60
x = 60 : 30
x = 2 Vậy x=2
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