\(\dfrac{1}{4}a^2-\dfrac{9}{25}=\left(\dfrac{1}{2}a-\dfrac{3}{5}\right)\left(\dfrac{1}{2}a+\dfrac{3}{5}\right)\)
\(\dfrac{1}{4}a^2-\dfrac{9}{25}\)
\(=\left(\dfrac{1}{2}a\right)^2-\left(\dfrac{3}{5}\right)^2\)
\(=\left(\dfrac{1}{2}a+\dfrac{3}{5}\right)\left(\dfrac{1}{2}a-\dfrac{3}{5}\right)\)
(Áp dụng hằng đẳng thức số 3)