13/6 cộng 7/4
\(=\dfrac{26}{12}+\dfrac{21}{12}=\dfrac{47}{12}\)
`13/6 + 7/4 = 26/12 + 21/12 = 47/12`
\(\dfrac{13}{6}+\dfrac{7}{4}=\dfrac{26}{12}+\dfrac{21}{12}=\dfrac{26+21}{12}=\dfrac{47}{12}\)
\(\dfrac{13}{6}+\dfrac{7}{4}\)=\(\dfrac{13.4}{6.4}+\dfrac{7.6}{4.6}=\dfrac{52}{24}+\dfrac{42}{24}=\dfrac{94}{24}=\dfrac{47}{12}\)