1243
+ 18239
19482 7
54 2783
58
22
1
\(1243+18239:7\)
\(=\dfrac{1243}{1}+\dfrac{18239}{7}\)
\(=\dfrac{8701}{7}+\dfrac{18239}{7}\)
\(=\dfrac{26940}{7}\)
1 243 + 18 239: 7
= 1 243 + 2 605.4
= 3 848.4
1243
+ 18239
19482 7
54 2783
58
22
1
\(1243+18239:7\)
\(=\dfrac{1243}{1}+\dfrac{18239}{7}\)
\(=\dfrac{8701}{7}+\dfrac{18239}{7}\)
\(=\dfrac{26940}{7}\)
1 243 + 18 239: 7
= 1 243 + 2 605.4
= 3 848.4
Chứng tỏ rằng số sau là hợp số:
a) 12431243....1243( 9 bộ 1243)
b) 12431243....1243( 17 bộ 1243)
Câu 4 : Bỏ ngoăc rồi tính
a) 173 - ( 36 + 27 ) + [ ( 175 - 173 ) - ( - 36 + 175 ) - 50 ]
b) - 428 - ( 176 - 2750 ) - [ 2750 - ( 176 + 482 ) ] - 147
c) [ ( 321 - 797 ) - ( - 371 + 1900 ) ] - 321 - [ 371 + ( - 797 ) ]
d) [ - ( 4625 + 1907 ) + ( - 164 + 4625 ) ] - [ ( 1243 - 1907 ) - 164 ]
GIÚP MINH NHA => MÌNH K
Tìm chữ số tận cùng:
74101 49500 81732 124335
7^1+7^2+7^3+7^4+7^5+7^6+7^7+7^8 chu so tan cung la may
7^1.7^2.7^3.........7^2016 khi chia cho 5 thi du may
7^1.7^2.7^3.........7^2016 khi chia cho 5 thi du may
cho a chia 7 du 3 . Hoi a binh phuong chia 7 du may
52013chia 7 du may
(7-x).(2019.2019.1024.12465.465768.97868.4464.9808087.5456.4.4533)=0
x bang may