không quy đồng thì tính như nào?
\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{16}\)
\(=1-\dfrac{1}{16}\)
\(=\dfrac{16}{16}-\dfrac{1}{16}\)
\(=\dfrac{15}{16}\)
Toán lớp 1 :))
\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{16}\)
\(=1-\dfrac{1}{16}\)
\(=\dfrac{15}{16}\)