Bài 1:
\(=18+48+2\cdot3\sqrt{2}\cdot4\sqrt{3}-8-27-2\cdot2\sqrt{2}\cdot3\sqrt{3}\)
=18+48-27-8
=10+21
=31
Bài 2:
\(\dfrac{x-\sqrt{x}-12}{3\sqrt{x}-12}=\dfrac{\left(\sqrt{x}-4\right)\left(\sqrt{x}+3\right)}{3\cdot\left(\sqrt{x}-4\right)}=\dfrac{\sqrt{x}+3}{3}\)