`1/8 + 3/8 + 9/8 = (1 + 3 + 9)/8 = 13/8`
\(\dfrac{1}{8}+\dfrac{3}{8}+\dfrac{9}{8}=\dfrac{13}{8}\)
\(\dfrac{1}{8}+\dfrac{3}{8}+\dfrac{9}{8}=\dfrac{1+3+9}{8}=\dfrac{13}{8}\)
\(\dfrac{\text{1}}{\text{8}}+\dfrac{3}{8}+\dfrac{9}{8}=\dfrac{1+3+9}{8}=\dfrac{13}{8}\)