Question

1) 64m³ - 27

2) 27 - y³

3) 125 + t³

Answer 1

\(1,64m^3-27=\left(4m-3\right)\left(16m^2+12m+9\right)\)

\(2,27-y^3=\left(3-y\right)\left(9+3y+y^2\right)\)

\(3,125+t^3=\left(5+t\right)\left(25-5t+t^2\right)\)

Answer 2

1) 64m³ - 27 = (4m)³ - 3³

= (4m - 3)(16m² + 12m + 9)

2) 27 - y³ = 3³ - y³

= (3 - y)(9 + 3y + y²)

3) 125 + t³ = 5³ + t³

= (5 + t)(25 - 5t + t²)